#319 Meeting Schedule II

Given an array of meeting intervals where intervals[i] = [start_i, end_i], find the minimum number of days needed to schedule all meetings without conflicts.

Rules:

• Multiple meetings can be scheduled on the same day if they don't conflict
• Meetings with common endpoints don't conflict
• All meetings must be scheduled
• Start time is always less than end time

Constraints:

• 0 ≤ intervals.length ≤ 500
• 0 ≤ start < end ≤ 1,000,000

Examples:

// Example 1:
console.log(
  minMeetingDays([
    [0, 40],
    [5, 10],
    [15, 20],
  ]),
);
// Output: 2
// Explanation:
// Day 1: [0,40]
// Day 2: [5,10], [15,20]

// Example 2:
console.log(minMeetingDays([[4, 9]]));
// Output: 1
// Explanation: Only one day needed for one meeting